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The Functional Programmer's Ascent to Abstraction
FunctionalProgramming Post #2211, on Oct 31, 2020 in TG

The Functional Programmer's Ascent to Abstraction

Why is this FunctionalProgramming meme funny?

Level 1: Dressing Up Simplicity

Imagine you have a really simple math problem: you want to take a number, square it, and then add the original number. For example, if the number is 2, you square it (2^2 = 4) and then add 2 to get 6. There are easy ways to do this, but the joke in this meme is that our friend Winnie the Pooh does it in three different ways, each more unnecessarily fancy than the last – and he gets more dressed up each time to match how overly fancy the method is!

In the first picture, Pooh is just normal Pooh sitting at a desk with a mug, and he solves the problem the normal way. That’s like you simply saying, “I take my number, square it, then add the number. Done.” It’s straightforward, like wearing your everyday clothes.

In the second picture, Pooh is suddenly wearing a nice tuxedo and acting smug. Now imagine someone solving the same simple math problem but in a super roundabout way just to show off. It’s as if a friend was asked, “What’s 5 squared plus 5?” and they start saying, “Well, if you take the sum of the elements after applying these two transformations…,” using big fancy words and a long process, but they still get the answer 30 in the end. They’re doing more work than needed, kind of like wearing a tuxedo to eat a bowl of cereal — silly and overly formal for something simple!

In the third picture, Pooh has gone full fancy-mode: he’s got a top hat, a monocle on one eye, and a curly mustache. He looks like a high-society gentleman from an old movie. This is like someone solving the same math problem in an even more absurdly complicated way, maybe speaking in old Shakespearean English or using a secret math trick that almost no one knows. It’s the equivalent of using an elaborate magic ritual just to add two numbers. He still gets the correct answer, but no one has any clue how he managed to do it without an explanation. It’s as if Pooh is saying, “Behold, I shall produce the answer by combining the cosmic forces of arithmetic,” when all he needed to do was basic math.

The funny part of this meme is that all three Poohs – the normal one, the tuxedo one, and the monocle one – are doing the same math, but the way they describe or perform it gets ridiculously complicated just for show. It’s like asking three people to explain how to tie their shoes:

  • Person 1 just says, “I tie a simple knot. Done.”
  • Person 2, in a suit, says, “First, I intertwine the left lace around the right in a looping fashion to create a secure knot.” (Sounds fancier but it’s the same result.)
  • Person 3, wearing a top hat and monocle, proclaims, “I shall perform a double-looping bunny-ear configuration followed by a symmetrical tension adjustment.” (Now it sounds really fancy and confusing, but they’re still just tying their shoes!)

In the end, all three shoes are tied, all three math problems are solved, all three pieces of code give the same answer. The humor comes from seeing how overly over-the-top Pooh gets in the second and third panels compared to the simple first one. We’re laughing at the idea of making something simple into something so unnecessarily complicated and pompous. It’s like dressing up in a tuxedo to do something ordinary – funny because it’s so extra! The meme playfully teases those situations where someone takes a basic task and adds a bunch of fancy flair to show off, even though it wasn’t needed. So, it’s basically saying: the first Pooh shows the normal way, and the final Pooh is way too proud of doing it in a super fancy way. It’s a silly joke about being fancy for no good reason, and even if you don’t follow the code, you can tell from Pooh’s expression and outfit in each panel that it’s getting absurd – and that’s why it’s funny!

Level 2: From Clear to Obscure

Let’s break down what’s happening in each panel in a more approachable way. The meme shows three Haskell code snippets that all do the same thing: take a number x, square it (x^2), and add the original number x, giving the result x² + x. In normal math, if x = 5, that would be $5^2 + 5 = 25 + 5 = 30$. Each panel’s code will give 30 when x is 5, just via different routes. What changes in each panel is how the code is written – from a very straightforward style to a very fancy and cryptic style. Winnie the Pooh gets more dressed up in each image to symbolize that the code is getting more pretentiously sophisticated.

  • Panel 1 (Pooh at the desk, normal): The code shown is (\x -> x^2 + x). This is a basic lambda expression in Haskell. A lambda creates an anonymous function. So \x -> x^2 + x means “a function that takes x and returns x^2 + x.” It’s similar to how you’d write a function in many languages; nothing unusual here aside from Haskell’s syntax (^2 means “squared”). This is the clear, direct way to define the function. Anyone reading it can tell immediately that it takes an input x and calculates one value. Pooh is just casually coding here, no fancy attire – because the code itself isn’t trying to be fancy.

  • Panel 2 (Pooh in a tuxedo): The code now is foldl1 (+) . ([id,(^2)] <*>) . (:[]). If you’re new to Haskell, this probably looks intimidating. Let’s unpack it step by step. In Haskell, . is the function composition operator — it means “take the output of the function on the right and pass it to the function on the left.” So we have three parts being composed: foldl1 (+) on the left, ([id,(^2)] <*>) in the middle, and (:[]) on the right. When you see something of the form (f . g . h) x, it means the same as f(g(h(x))). So here, given an input x, first (:[]) will be applied to x, then ([id,(^2)] <*>) to that result, then foldl1 (+) to that result. Now what are those parts?

    • (:[]) is a quirky way to turn something into a one-element list. (:) is the list “cons” operator (it adds an element to the front of a list). [] is an empty list. So x : [] produces a list containing x. Writing (:[]) by itself is a section in Haskell – it’s like a function that takes something and does something : []. So effectively, (:[]) is the function “put given element into a single-element list.” If you give (:[]) the number 5, it returns [5].

    • ([id, (^2)] <*>) is using the <*> operator with a list on the left side. In Haskell, <*> is an operator from the Applicative type class. For lists, fs <*> xs means: take each function in list fs and apply it to each value in list xs, collecting all results in a new list. So [id, (^2)] is a list of two functions: id (the identity function, which returns its input unchanged) and (^2) (a function that squares its input). If we have a list with a single value [x] and do [id, (^2)] <*> [x], the result will be [id x, (^2) x] i.e. [x, x^2]. It’s like we are saying "take x, and produce a list of two results: one by applying the identity function (so just x), and one by applying the squaring function (x^2)". In our composition chain, after (:[]) we will have [x], so then ([id,(^2)] <*>) yields [x, x^2].

    • foldl1 (+) means “fold (or reduce) the list using the + operation, starting with the first element”. foldl1 is a Haskell function that takes a list and a combining operation and applies it between all elements of the list from left to right. If the list is [a, b, c], then foldl1 f would compute ((a fb)f c). Here f is +, so foldl1 (+) [x, x^2] computes (x + x^2), since the list has two elements. Essentially it sums up the list. So after the previous step gave [x, x^2], this step adds them together, yielding x + x^2.

    Putting it all together, for some input number x:

    1. (:[]) makes it [x].
    2. ([id,(^2)] <*>) turns [x] into [x, x^2].
    3. foldl1 (+) reduces [x, x^2] to x + x^2.

    The end result is the same as before, but wow, the code is much more convoluted, right? There’s no explicit x anywhere; instead, it’s chaining higher-order functions. This is what we call point-free style: we define the function without ever mentioning the point (the argument) explicitly. It’s like a puzzle – each symbol is doing some work to transform the input behind the scenes. Haskell veterans might recognize this immediately, but newcomers would likely scratch their heads. Pooh in the tuxedo is metaphorically saying, “I’ve made this fancier.” The tux represents that this code is a bit full of itself: it’s more impressive-looking but arguably less straightforward. It’s like using a dozen-dollar word when a five-cent word would do, just to show you can. In fact, this panel is poking at code obfuscation: the code works, but it’s intentionally written in a convoluted way that’s hard to read for the uninitiated.

  • Panel 3 (Pooh with top hat and monocle): The final code snippet is (*) <*> (+1). This one is super terse – only 7 characters if you exclude spaces! To understand this, you need to know a bit about how Haskell treats functions as values. Here, (*) by itself is a function that takes a number and returns another function (specifically, if you supply one number to (*), it returns a function waiting for the second number — that’s called partial application). Similarly, (+1) is a function that takes a number and returns that number plus one. So we have two functions: one that multiplies by something, and one that adds one. Now <*> comes into play again, but this time with these functions. When we use <*> with functions (not lists, but functions), it has a specific behavior: (f <*> g) is a new function that, when given an input x, will compute f x (g x). This is part of the Applicative Functor instance for functions in Haskell. It sounds complicated, but let’s apply it here: let f = (*) and g = (+1). Then (f <*> g) x becomes f x (g x). Substituting f and g: that’s (*) x ((+1) x). Now (*) x y means x * y (multiplying x and y), and (+1) x means x + 1. So altogether, (*) x ((+1) x) becomes x * (x + 1). That’s exactly x² + x! So (*) <*> (+1) defines a function that for any input x returns x * (x+1).

    In more human terms: this code is using a fancy operator <*> to feed the same input to two different operations (* and +1) and then combine the results. It’s like an ultra-compact way to say “take x, compute x and also compute x+1, then multiply those two results together.” Notably, it achieves this without talking about x at all in the code. It’s point-free and relies on Haskell’s deeper features.

    This final form is arguably the most abstract and hardest to immediately grok. It’s something you might see and say, “What on Earth does that do?” until you know the trick. When Pooh wears the top hat, monocle, and mustache, it’s the meme’s way of saying this is high-brow code. He looks like an old-school aristocrat or a professor — someone who might say, “Indubitably, my dear,” and insist on doing things in the most refined (if overly complicated) way. The code (*) <*> (+1) is certainly refined in a Haskell sense: it’s leveraging the language’s purely functional nature and rich operator overloading to compress logic into a tiny, elegant package. But it’s also the kind of code that can make other programmers groan or laugh, because it’s doing something simple in a way that only makes sense if you’re in on the Haskell joke.

In summary, the meme’s three panels show three ways to write the same function in Haskell, each one more abstract than the last:

  1. A clear, direct lambda function (\x -> ...).
  2. A point-free composition using list applicative and fold.
  3. A super-compact applicative functor expression.

The joke is that Haskell (and functional programming in general) gives you incredible flexibility in how to express a computation. As you gain experience, you learn these wild techniques – but just because you can write something in a very roundabout, “smart” way doesn’t always mean you should. The humor is in the contrast: the first version is something any programmer would understand at a glance, while the last version is like a secret code that only seasoned Haskellers can decipher quickly. It’s a lighthearted poke at the functional programming culture: sometimes insiders pride themselves on writing code that looks like a work of art or a puzzle. If you’re newer to Haskell, don’t worry if the second and third panels look alien; that’s part of the fun of the meme. It’s basically saying “Haskell wizards will sometimes do this just to feel fancy.” And if you are a Haskell wizard, you’re probably both proud and a little embarrassed to admit you find the last one elegant! This mix of admiration and eye-rolling is exactly why the meme is popular among developers — it’s coding humor that plays with the gap between simple solutions and show-off solutions.

Level 3: Point-Free Prestige

For seasoned developers, this meme hits on the hilarious dichotomy of clear code vs clever code. All three Haskell snippets compute the same thing – the function f(x) = x² + x – but the style evolves from a plain lambda to an increasingly obfuscated one-liner. Why is this funny? Because it riffs on a well-known pattern in the Haskell and functional programming community: the tendency to show off with ultra-concise, point-free style solutions that only a functional programming aficionado would immediately understand.

In the first panel, we have a straightforward anonymous function (\x -> x^2 + x). Even someone with basic programming knowledge can parse this: it squares x and adds x. Pooh is at a regular desk with a coffee mug, your everyday coder writing a simple lambda expression. No fuss, no fanfare – this is the baseline, obvious implementation.

Now enter panel two: Pooh dons a tuxedo and a smug look, and the code beside him reads foldl1 (+) . ([id,(^2)] <*>) . (:[]). This is already a step into the arcane for those not familiar with Haskell’s functional programming concepts. A Haskell veteran would smirk at this because it’s a technically clever but insanely roundabout way to do $x^2 + x$. It’s using function composition (the .) to glue together several operations without naming any variables. This snippet is exploiting language quirks like partial application of list constructors (:[]) and the <*> operator on lists. It’s the kind of thing you might see in a code golf challenge or from a Haskell enthusiast who enjoys pushing the limits of terse code. Experienced devs recognize the pattern: it’s deliberately obscure code that screams “I know my Haskell tricks!” The humor lies in that paradoxical pride – the code is both impressively clever and practically impractical. In a code review, a senior might chuckle and then say, “Great, it works... now how about we rewrite that so the rest of the team can understand it?” It satirizes a form of code elitism: using intellectual flexing over straightforward solutions.

Finally, panel three: Pooh has ascended to full aristocracy with a top-hat, monocle, and mustache. The code (*) <*> (+1) is as terse and elite as it gets. To non-Haskell programmers, this might look like line noise or an emoji shrug, but to Haskell insiders, it’s the pièce de résistance – a pure point-free expression leveraging Applicative Functors. Here Pooh basically says, “I can compute x²+x using nothing but function applicative composition, behold!” This one-liner relies on the obscure knowledge that in Haskell, the function type itself is an instance of the Applicative type class. In plainer words, (*) and (+1) are each functions, and the <*> operator combines them into a new function that feeds the same input to both and then uses the first function’s result as a function to apply to the second’s result. It’s mind-bending until you’ve seen it: (*) <*> (+1) effectively produces \x -> x * (x+1). Senior devs who know Haskell will recognize this as both brilliant and ridiculously cryptic. It’s a power move – the kind of code you might pull out to impress your FP friends at the cost of anyone else scratching their head.

The meme’s progression exaggerates a real dynamic in programming culture: syntax humor that pokes fun at how far experts will go to make code technically shorter or more abstract, even if it becomes harder to read. It’s common in Haskell circles (or any FunctionalProgramming forum) to see playful one-upmanship: “Oh, you used a lambda? Amateur. Let’s see if we can do it point-free.” Each panel is essentially the same computation dressed in fancier attire, much like Pooh’s increasingly luxurious clothing. There’s a relatable sense of inside joke here: Haskell and functional programming aficionados pride themselves on understanding these esoteric forms, while others roll their eyes or laugh. As a community, we both admire and mock this elitism. On one hand, it’s genuinely cool that Haskell’s rich abstractions allow such concise expressions. On the other hand, we all know readability and maintainability suffer when you write code like a riddle.

Smug Pooh (in tuxedo): “Oh, you wrote a simple lambda for that? How quaint. Watch me condense it with some foldl1 composition magic.”
Monocle Pooh (top-hat): “Dear fellow, real connoisseurs of Haskell use <*> and dispense with arguments entirely. Simply exquisite, isn’t it?”

These imaginary quotes capture the meme’s tone – a tongue-in-cheek portrayal of the pretentious high horse some might get on with overly clever code. Seasoned devs find this funny because they’ve seen it in the wild: maybe in that one absurdly dense open-source library, or in code-golf competitions, or even in their own earlier code when they were over-eager to use a fancy new trick. The meme is a mirror to those shared experiences. It highlights how language quirks unique to Haskell (like treating functions as applicatives, or the ability to overload operators like <*> in creative ways) can be both a source of power and a source of comedic frustration. In essence, it’s poking fun at the Haskell high society – those who delight in turning simple tasks into an exhibition of knowledge. And if you’ve ever been down the Haskell rabbit hole, you can’t help but laugh and nod in agreement.

Level 4: Combinator Chic

At the highest levels of functional programming elegance, this meme showcases a kind of mathematical couture in code. Haskell encourages a point-free (aka tacit) style where functions are composed without ever naming their inputs, harkening back to the deep roots of lambda calculus and combinatory logic. In fact, the transformation from (\x -> x^2 + x) to (*) <*> (+1) is a journey from an explicit lambda expression to a pure combinator form. The final form (*) <*> (+1) is essentially the S combinator from combinatory calculus in action! To see this, recall that Haskell’s <*> for functions is defined such that for any functions f and g:

-- For functions, the Applicative instance defines:
(f <*> g) x = f x (g x)

So, if we let f = (*) and g = (+1), then (f <*> g) x = (*) x ((+1) x), which simplifies to x * (x + 1) – exactly our target formula x² + x. This point-free purism leverages the Applicative Functor instance of the function type (->). In category theory terms, functions form an applicative functor where <*> is a way to apply a function-valued function to a function-valued argument. It’s a high-minded concept: treating functions themselves as contextual computations that can be combined. The resulting code has a mathematical beauty to those in the know – it’s concise and relies on abstract algebraic laws built into Haskell’s design.

The middle snippet, foldl1 (+) . ([id,(^2)] <*>) . (:[]), is another case of point-free wizardry. It exploits the List Applicative and composition to achieve the same result. Here, ([id, (^2)] <*>) . (:[]) creates a function that takes an input x, makes it a single-element list (:[]){x} (that’s what (:[]) does as a section), then uses the list <*> to apply each function in the list [id, (^2)] to that single x. The outcome is a list containing [id x, (^2) x], i.e. [x, x^2]. Then foldl1 (+) will fold (reduce) that list by summing all elements, effectively computing x + x^2. The entire composition is point-free: notice there’s no explicit mention of x at all. This style is powerful—function composition (.) and higher-order functions like foldl1 allow building complex operations from simpler pieces, much like composing mathematical functions. It resonates with hardcore functional programmers because it echoes formal function algebra and even category theory (thinking in terms of composition, functors, and monoids).

Historically, such point-free expressions connect to the very foundations of functional programming. Back in the 1930s, Schönfinkel and Curry showed that all lambda calculus (functions with named parameters) could be transformed into combinators (no named parameters) – a discovery that underpins what we see in these Haskell tricks. The Haskell community, influenced by academic research, has embraced these abstractions: Applicative and Functor come from category theory (where they’re morphisms and endofunctors on the category of types). The meme’s increasingly elitist code style is like a nod to that rich theoretical lineage. It’s as if Pooh is climbing the ladder of abstraction: from straightforward lambda calculus (Level 1 Pooh) up into the lofty heavens of category theory (Monocle Pooh). The humor comes from the absurdity of using such heavy theoretical machinery to do something as simple as add a number to its square. It’s both a celebration and a gentle roast of Haskell’s expressiveness — only Haskell (and a few other Languages in the FP world) would enable such baroque one-liners.

Description

A three-panel 'Tuxedo Winnie the Pooh' meme illustrating different levels of sophistication in functional programming. The first panel shows a regular Winnie the Pooh next to a simple Haskell-style lambda function: '(\x -> x^2 + x)'. The second panel features a more dapper Pooh in a tuxedo, alongside a more complex but equivalent function using function composition, applicative functors, and a fold: 'foldl1 (+) . ([id, (^2)] <*>) . (:[])'. The final panel displays the most sophisticated Pooh with a top hat and monocle, paired with an extremely terse, point-free applicative version: '(*) <*> (+1)'. All three code snippets compute the same mathematical function, f(x) = x² + x. The meme humorously critiques the developer's journey from writing clear, readable code to employing highly abstract, esoteric language features that are powerful but often sacrifice clarity for cleverness. It's a joke that resonates with senior engineers who have witnessed or participated in the tendency to over-engineer solutions with advanced theoretical concepts

Comments

38
Anonymous ★ Top Pick The final version is what you write after a sudden, life-altering epiphany about monoids. It's perfect, and only God and you understand why it works. Six months later, only God understands
  1. Anonymous ★ Top Pick

    The final version is what you write after a sudden, life-altering epiphany about monoids. It's perfect, and only God and you understand why it works. Six months later, only God understands

  2. Anonymous

    Haskell PR lifecycle: λx→x²+x ships, foldl1 (+) . ([id,(^2)] <*>) . (:[]) wins conference slots, (*) <*> (+1) earns you a 3 a.m. pager because elegance doesn’t answer on-call

  3. Anonymous

    The real sophistication is when you realize all three expressions compute x² + x, but only the last one makes your code review take three hours while everyone pretends to understand applicative functors

  4. Anonymous

    The evolution from lambda to point-free is like refactoring your resume: each iteration removes more explicit detail while somehow conveying you're more qualified. By the time you reach '(*) <*> (+1)', you've achieved peak Haskell - mathematically elegant, theoretically beautiful, and absolutely incomprehensible to your future self at 3 AM during an incident. It's the functional programming equivalent of wearing a monocle: technically superior, but everyone knows you're just showing off that you understand applicative functors

  5. Anonymous

    Pro tip: when '(\x -> x^2 + x)' becomes '(*) <*> (+1)', you’ve optimized for laws, not humans - Applicative (->) a impresses the typeclass, terrifies the on‑call

  6. Anonymous

    Refactor request: “make it point‑free.” So λx. x^2 + x became ((*) <*> (+1)); same semantics, higher categorical elegance, and the bus factor vanished alongside the variable

  7. Anonymous

    From algebra desk jockey to foldl aristocrat: Pooh abstracts your poly into operator chic

  8. @lowerkinded 5y

    i thought im the only subscriber who knows haskell

    1. @bit69tream 5y

      main :: IO () main = hPutStrLn "no"

    2. Deleted Account 5y

      I studied it

    3. @Ahmed_K_3301 5y

      U still don't understand monad

      1. @p4vook 5y

        monads are easy

  9. @romanovich_dev 5y

    Wtf?

    1. @doorhinge 5y

      +1

    2. @p4vook 5y

      Haskell

  10. @RiedleroD 5y

    I have no idea what that code does and that scares me

    1. @p4vook 5y

      well, it's basically a composition of two functions: f(y) = x * y and f(x) = x + 1

      1. @RiedleroD 5y

        thanks

      2. @p4vook 5y

        .

  11. @p4vook 5y

    lol

  12. @fdrov 5y

    Python 3.9 list comprehension?

    1. @cheese_hs 5y

      Python 9.3

      1. @bee_vie 5y

        Rather Python -3.9

        1. Deleted Account 5y

          Python 1939 go brrr

          1. @lord_nani 5y

            Can repeat

          2. @mvolfik 5y

            Python 3.6 not great not terrible

      2. @delimitry 5y

        😂😂😂

  13. @sharp_mechanix 5y

    wtf is that?

    1. @romanovich_dev 5y

      As per comments - Haskell

  14. @sharp_mechanix 5y

    looks like egyptian scripts

  15. @p4vook 5y

    Last example in here is a composition of two functions (+1) and (*)

  16. @FiveMetres 5y

    But why?..

  17. @lord_nani 5y

    lmaooooo, haskell

  18. Deleted Account 5y

    Common Lisp go brrr

  19. Deleted Account 5y

    Racket is cool too

    1. @bit69tream 5y

      #lang python go brrr

      1. Deleted Account 5y

        "listen here, you litte shit"

    2. @mvolfik 5y

      What is actually racket used for? My dad (also programmer) taught me absolute programming basics in racket, but that's where me and racked ended. I speak mostly python now

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